RCC COLUMN DESIGN

RCC COLUMN DESIGN

ASSUME THE LENGTH OF COLUMN AND FOOTINGS IS ABOUT 19 FEET

THE COLUMN SIZE IS (2' X 1.5') 

THE ROD WHICH WE ARE GOING TO USE IS 20MM,16MM, AND 8MM FOR STIRRUPS

THE DENSITY OF STEEL FOR 

20MM=2.5 KG/M

16MM = 1.6 KG/M

8MM = 0.4 KG /M

LET US CALCULATE THE STEEL REQUIRED OF ONE COLUMN.

STEEL BAR SIZE = DENSITY OF BAR * LENGTH OF COLUMN * NUMBER OF BARS

LET US CONVERT THE LENGTH OF BAR IN  TO METERS

19' * 0.3 = 5.7 M

20MM ROD = 2.5 KG/M * 5.7 M * 4 = 57 KG (APPROXIMATELY 1 BUNDLE)
16MM ROD = 1.6 KG/M * 5.7 M * 4 = 37 KG (APPROXIMATELT 2 RODS)

8MM ROD FOR STIRUPS @ C/C OF 0.5'

TOTAL WE REQURIE 30 STIRUPS

CUTTING LENGTH OF ROD 2'+1.5'+2'+1.5'= 7'+ 1' = 8'

8' * 0.3M = 2.7M

8MM ROD = 0.4 * 2.7 * 30 = 32.4 KG ( APPROXIMATELY 14 RODS)

*(1 TMT STEEL ROD IS OF 45' IN LENGTH)*

STAIR DESIGN

STAIRCASE DESIGN

HOW TO DESIGN A STAIRCASE

CONSIDER YOU HAVE STAIRCASE ROOM  OF 4.5M X 2.0M AND HEIGHT OF THE ROOM IS 3.0M

SIZE OF THE ROOM = 4.5M X 2.0 M
HEIGHT = 3.0 M
ASSUMING WIDTH OF THE STAIRCASE AS 1.0M

PROVIDE TWO FLIGHT WITH MID LANDING HEIGHT OF EACH FLIGHT
                      = 3.0 / 2 = 1.5 M

ASSUME 15 CM RISERS

NO OF RISERS REQURIED IS = 150 / 15 = 10 NOS

ASSUMING 25 CM TREAD

LENGTH OF THE FLIGHT = (10-1) 25 = 225 CM

WIDTH OF LANDING  = 1.0M

SPACE LEFT FOR PASSAGE  = (4.5-1-2.25) = 1.25 M

SO PROVIDE

25CM TREAD AND 15CM RISERS WITH 1.0M WIDE MID LANDING.

20X40 HOUSE FRONT ELEVATION

800 SFT HOUSE ELEVATION